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Haryana PMT Haryana PMT Solved Paper-2004

  • question_answer
    \[20g\]of a binary electrolyte (mol. \[wt=100\]) are dissolved in \[500g\]of water.         The depression in freezing point of the solution is \[{{0.74}^{o}}C\]\[({{K}_{f}}=1.86K\,molalit{{y}^{-1}})\] The degree of ionization of the electrolyte is:

    A)  \[0%\]                                 

    B)  \[100%\]

    C)  \[75%\]                              

    D)  \[50\]           

    Correct Answer: A

    Solution :

                    \[\Delta T=\frac{1000\times {{K}_{f}}\times \omega }{m\times 500}\] \[0.74=\frac{1000\times 1.86\times 20}{m\times 500}\]                 \[m=100\] Actual molecular mass = 100 \[\therefore \] The degree of ionization of the electrolyte is 0%.       


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