A) \[50ml\]
B) \[5.0ml\]
C) \[0.50\text{ }ml\]
D) \[100ml\]
Correct Answer: A
Solution :
For complete neutralization, m. eq of \[{{H}_{2}}S{{O}_{4}}\]m. eq. of \[NaOH\] \[0.1\times 2\times V=50\times 0.2\times 1\] ( \[\because \] \[0.1\,M{{H}_{2}}S{{O}_{4}}=0.2N\,{{H}_{2}}S{{O}_{4}}\]) \[V=50ml\]
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