Haryana PMT Haryana PMT Solved Paper-2004

  • question_answer
    For the cell,\[TI+T{{I}^{+}}(0.01M)||{{C}^{2+}}(0.1)M|Cu\]\[{{E}_{cell}}\] at x\[{{25}^{o}}C\] is \[0.83V\]. \[{{E}_{cell}}\]can be increased:

    A)  by decreasing \[[C{{u}^{2+}}]\]

    B)  by increasing \[[C{{u}^{2+}}]\]

    C)  by increasing \[[T{{I}^{+}}]\]

    D)  none

    Correct Answer: B

    Solution :

                    \[{{E}_{cell}}={{E}^{o}}_{cell}+\frac{0.0592}{n}\log \frac{[C{{u}^{2+}}]}{{{[T{{i}^{+}}]}^{2}}}\]\[n=2\] \[\therefore \] According to above eq. \[{{E}_{cell}}\] can be increased by increasing \[[C{{u}^{2+}}]\]   \[\]


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