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Haryana PMT Haryana PMT Solved Paper-2003

  • question_answer
    The minimum magnifying power of a telescope is M. If the focal length of the eye lens is halved. The magnifying power will become :

    A)  \[\frac{M}{4}\]                                

    B)  3M

    C)  2M                                       

    D)  4M

    Correct Answer: C

    Solution :

                    Minimum magnifying power \[M=\frac{{{f}_{o}}}{{{f}_{e}}}\] Hence, if \[{{f}_{e}}\] is halved, then                 \[\frac{M}{M}=\frac{{{f}_{o}}}{fe/2}\times \frac{fe}{fo}=2\] \[\Rightarrow \]               \[M=2M\]


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