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Haryana PMT Haryana PMT Solved Paper-2003

  • question_answer
    A body of mass 1 kg is rotating in a vertical circle of radius 1 m. What will be the difference in kinetic energy at the top and at the bottom of the circle? \[(\text{take}\,g=10\text{ }m/{{s}^{2}})\] :

    A)  50 J                                       

    B)  30 J

    C)  20J                                        

    D)  10J

    Correct Answer: C

    Solution :

                    We know that velocity at the top is \[\sqrt{gr}\]and that at the bottom is \[\sqrt{5gr}\]gr Now difference in \[K.E.=\frac{1}{2}m[5gr-gr]=2mgr\] \[=2\times 1\times 10\times 1=20J\]


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