A) twice the vertical height
B) vertical height
C) four times the vertical height
D) three times of vertical height
Correct Answer: C
Solution :
\[R=\frac{{{u}^{2}}{{\sin }^{2}}{{90}^{o}}}{g}=\frac{{{u}^{2}}}{g}\] ??.(1) and \[H=\frac{{{u}^{2}}{{\sin }^{2}}{{45}^{o}}}{2g}=\frac{{{u}^{2}}}{4g}\] ??..(2) Dividing Eq. (1) by Eq. (2), \[\frac{R}{H}=4\] or \[R=4H\]
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