question_answer

If the concentration of \[M{{g}^{2+}}\] is \[0.01M\], the electrode potential of \[M{{g}^{2+}}/Mg\]electrode will be (Given that \[{{E}^{o}}M{{g}^{2+}},\,Mg=-2.36V\]):

A)  \[+2.80\]                            

B)  \[-2.80\]

C)  \[4-2.41\]                          

D)  \[-2.41\]