A) 5 year
B) 7.5 year
C) 12 year
D) 25 year
Correct Answer: C
Solution :
According to Keplers law \[{{T}^{2}}\propto {{R}^{3}}\] \[{{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{2}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{3}}={{\left( \frac{5.2{{r}_{1}}}{{{r}_{1}}} \right)}^{3}}={{(5.2)}^{3}}\] \[{{T}_{2}}={{T}_{1}}{{(5.2)}^{3/2}}\] \[={{T}_{1}}\times 11.85=1\times 11.85\] \[=11.85\] years \[=12\] years.
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