A) \[1.2\times {{10}^{-10}}M\]
B) \[1.2\times {{10}^{-9}}M\]
C) \[1.2\times {{10}^{-6}}M\]
D) \[0.1M\]
Correct Answer: B
Solution :
\[{{K}_{sp}}=[N{{a}^{+}}][C{{l}^{-}}]\] \[=1.2\times {{10}^{-10}}=[s][0.1]\] \[{{K}_{\sup }}=s\times 0.1=1.2\times {{10}^{-10}}\] or \[s=\frac{1.2\times {{10}^{-10}}}{0.1}=1.2\times {{10}^{-9}}M\]
You need to login to perform this action.
You will be redirected in
3 sec
