A) \[12.5\times {{10}^{-12}}N\]
B) \[5\times {{10}^{-12}}N\]
C) \[9\times {{10}^{-12}}N\]
D) none of these
Correct Answer: B
Solution :
Using the relation, \[F=e\upsilon \,\,B\,\,\sin \theta \] ...(i) Here, \[\upsilon =2.5\times {{10}^{7}}m/s,\,B=2.5T,\,\theta ={{30}^{o}}\] \[e=1.6\times {{10}^{-19}}\] Putting the values in equation (i) weight or \[F=1.6\times {{10}^{-19}}\times 2.5\times {{10}^{7}}\times 2.5\sin {{30}^{o}}\] or \[F=1.6\times {{10}^{-19}}\times 2.5\times {{10}^{7}}\times 2.5\times \frac{1}{2}\] So, \[F=5\times {{10}^{-12}}N\]
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