A) 600 V
B) 400 V
C) 100 V
D) 200 V
Correct Answer: B
Solution :
The common potential is given by \[V=\frac{{{C}_{1}}{{V}_{1}}+{{C}_{2}}{{V}_{2}}}{{{C}_{1}}+{{C}_{2}}}\] Here, \[{{C}_{1}}=20\mu F=20\times {{10}^{-6}}F\] \[{{V}_{1}}=500V,\,{{C}_{2}}=10\mu F=10\times {{10}^{-6}}F,\] \[{{V}_{2}}=200V\] or \[V=\frac{(20\times {{10}^{-6}}\times 500)+(10\times {{10}^{-6}}\times 200)}{20\times {{10}^{-6}}+10\times {{10}^{-6}}}\] \[V=400V\]
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