A) 0.5 eV
B) 1 eV
C) 10.4 eV
D) 1820 eV
Correct Answer: B
Solution :
Magnetic flux = magnetic field \[\times \] area Dimensions of magnetic flux \[=\frac{F}{il}\times {{l}_{2}}=\frac{[ML{{T}^{-2}}]}{[L][A]}\times {{L}^{2}}\] \[{{\phi }_{B}}=[M{{L}^{2}}{{T}^{-2}}{{A}^{-1}}]\]
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