A) \[V=KT\]
B) \[{{V}_{1}}={{V}_{0}}\frac{{{T}_{0}}}{{{T}_{t}}}\]
C) \[{{V}_{t}}={{V}_{0}}\left( 1+\frac{t}{273} \right)\]
D) \[{{\left( \frac{{{\partial }^{2}}V}{\partial {{T}^{2}}} \right)}_{p}}=6\]
Correct Answer: B
Solution :
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