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Haryana PMT Haryana PMT Solved Paper-1999

  • question_answer
    The   oxidation   number   of  Pt   in \[{{[Pt({{C}_{2}}{{H}_{4}})C{{l}_{3}}]}^{-}}\]is:     

    A)  \[+1\]                                  

    B)  \[+4\]

    C)  \[+2\]                                  

    D)  \[+3\]

    Correct Answer: C

    Solution :

                    In \[{{[Pt\,({{C}_{2}}{{H}_{4}})C{{l}_{3}}]}^{-}}\] suppose the oxidation number of  Pt is x \[x+0(-1\times 3)=-1\](\[\because \] oxidation state of\[{{C}_{2}}{{H}_{4}}\]is zero)                 \[x-3=-1\]                 \[x=+2\]


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