A) \[{{10}^{-7}}m/s\]
B) \[{{10}^{-5}}m/s\]
C) \[{{10}^{-2}}m/s\]
D) \[{{10}^{-}}^{3}m/s\]
Correct Answer: D
Solution :
Using the -relation, \[i=neA{{\upsilon }_{d}}\] \[n={{10}^{29}}\] where, \[A=1m{{m}^{2}}=1\times {{10}^{-6}}{{m}^{2}}\] \[i=20amp\,\,e=1.6\times {{10}^{-19}}C\] So, \[{{\upsilon }_{d}}=\frac{i}{neA}\] \[=\frac{20}{{{10}^{29}}\times 1.6\times {{10}^{-19}}\times {{10}^{-6}}}={{10}^{-3}}m/s\]
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