A) \[574{}^\circ \]
B) \[590{}^\circ \]
C) \[287{}^\circ \]
D) \[-80{}^\circ \]
Correct Answer: A
Solution :
Using the relation, \[\frac{F-32}{180}=\frac{K-273}{100}\] So, \[\frac{\theta -32}{{{180}^{o}}}=\frac{\theta -273}{100}\] \[100\theta -3200=180\theta -49140\] \[80\theta =45940\] So, \[\theta =574.25\] or \[\theta ={{574}^{o}}\]
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