A) \[{{H}_{2}}Cr{{O}_{4}},\,{{H}_{2}}C{{r}_{2}}{{O}_{7}}\]
B) \[{{H}_{2}}C{{r}_{2}}{{O}_{7}},\,C{{r}_{2}}{{O}_{3}}\]
C) \[CrO_{4}^{2-},\,CrO_{7}^{2-}\]
D) \[{{H}_{2}}Cr{{O}_{4}},\,CrO_{4}^{2-}\]
Correct Answer: D
Solution :
\[Cr{{O}_{3}}+{{H}_{2}}O\xrightarrow{{}}\underset{(A)}{\mathop{{{H}_{2}}Cr{{O}_{4}}}}\,\xrightarrow{O{{H}^{-}}}\underset{(B)}{\mathop{CrO_{4}^{2-}}}\,\]
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