A) ethyl cyanide
B) ethyl amine
C) methyl amine
D) acetamide
Correct Answer: B
Solution :
\[\underset{\text{Ethyl}\,\,\text{amine}}{\mathop{{{C}_{2}}{{H}_{5}}N{{H}_{2}}}}\,\xrightarrow{HN{{O}_{2}}}\underset{(A)}{\mathop{\underset{\text{Ethyl}\,\,\text{alcohol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,}}\,\] \[\xrightarrow{PC{{l}_{5}}}\underset{(B)}{\mathop{\underset{\text{Ethyl}\,\,\text{chloride}}{\mathop{{{C}_{2}}{{H}_{5}}Cl}}\,}}\,\xrightarrow{N{{H}_{3}}}\underset{(C)}{\mathop{\underset{\text{Ethyl}\,\,\text{amine}}{\mathop{{{C}_{2}}{{H}_{5}}N{{H}_{2}}}}\,}}\,\]
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