CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    If a compound on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is

    A)  \[C{{H}_{2}}OCl\]                           

    B)  \[C{{H}_{2}}Cl{{O}_{2}}\]

    C)  \[ClC{{H}_{2}}O\]                           

    D)  \[CHClO\]

    Correct Answer: D

    Solution :

              \[C:H:Cl:O=\frac{18.5}{12}:\frac{1.55}{1}:\frac{55.04}{35.5}:\frac{24.81}{16}\] \[=1:1:1:1\]


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