A) \[Na,\,Mg\]
B) \[{{O}^{2-}},\,{{N}^{3-}}\]
C) \[L{{i}^{+}},\,B{{e}^{2+}}\]
D) \[B{{a}^{2+}},\,S{{r}^{2+}}\]
Correct Answer: B
Solution :
\[{{O}^{2-}}\] and \[{{N}^{3-}}\] both are isoelectronic but differ in the charge possessed by them. As the negative charge increases, the electrons are held less and less tightly by the nucleus, therefore, radius increases from \[{{O}^{2-}}\]to \[{{N}^{3-}}\].
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