CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    An electron, a proton and an alpha particle have KE of 16E, 4E and E respectively. What is the qualitative order of their de-Broglie wavelengths?

    A)  \[{{\lambda }_{e}}>{{\lambda }_{p}}>{{\lambda }_{\alpha }}\]                  

    B)  \[{{\lambda }_{p}}={{\lambda }_{\alpha }}>{{\lambda }_{e}}\]

    C)  \[{{\lambda }_{p}}<{{\lambda }_{e}}>{{\lambda }_{\alpha }}\]                  

    D)  \[{{\lambda }_{\alpha }}<{{\lambda }_{e}}\approx {{\lambda }_{p}}\]

    Correct Answer: A

    Solution :

              \[\lambda =\frac{h}{mv},\]i.e., \[\lambda \propto \frac{1}{\sqrt{mv}}\]and \[m>>E\] Thus, correct order is\[{{\lambda }_{e}}>{{\lambda }_{p}}>{{\lambda }_{\alpha }}\]


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