A) \[{{V}_{A}}-{{V}_{O}}=\frac{B\omega \,{{l}^{2}}}{2}\]
B) \[{{V}_{O}}-{{V}_{C}}=\frac{9}{2}B\omega \,{{l}^{2}}\]
C) \[{{V}_{A}}-{{V}_{C}}=4B\omega \,{{l}^{2}}\]
D) \[{{V}_{C}}-{{V}_{O}}=\frac{9}{2}B\omega \,{{l}^{2}}\]
Correct Answer: C
Solution :
\[{{V}_{0}}-{{V}_{A}}=\frac{B\,\omega \,I}{2}\times I\] \[=\frac{B\,\omega \,{{I}^{2}}}{2}\] \[{{V}_{0}}-{{V}_{A}}=\frac{B\,\omega 3I}{2}\times 3I\] \[=\frac{9B\,\omega \,{{I}^{2}}}{2}\] \[{{V}_{A}}-{{V}_{c}}=4B\omega \,{{I}^{2}}\]
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