A) 200 m/s
B) 100 m/s
C) 400 m/s
D) 300 m/s
Correct Answer: C
Solution :
\[R=\frac{{{u}^{2}}\sin 2\theta }{g}\] \[R=\frac{{{u}^{2}}\sin 90{}^\circ }{g}\] \[\mu =\sqrt{Rg}\] \[=\sqrt{16\times {{10}^{3}}}\times 10\] \[=400\,m\text{/}s\]
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