2. Solved Papers
  3. CMC Medical

CMC Medical CMC-Medical VELLORE Solved Paper-2014

  • question_answer
    Each of the two points charges are doubled and their distance is halver force of interaction becomes n times , where n is

    A)  4                                            

    B)  1            

    C)  1/16                                     

    D)  16

    Correct Answer: D

    Solution :

                    \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\] \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{2\,{{q}_{1}}2{{q}_{2}}}{{{(r/2)}^{2}}}=\left( \frac{4}{1/4} \right)F\] \[nF=16F,\]\[n=16\]


You need to login to perform this action.
You will be redirected in 3 sec spinner