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CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    \[{{K}_{a}}\] for HF is \[3.5\times {{10}^{-7}}\]calculate \[{{K}_{b}}\] for the fluoride ion.

    A)  \[3.5\times {{10}^{-4}}\]                             

    B)  \[1.0\times {{10}^{-7}}\]

    C)  \[2.85\times {{10}^{-11}}\]                        

    D)  \[1.0\times {{10}^{-14}}\]

    Correct Answer: C

    Solution :

                    For a conjugate acid-base pair: \[{{K}_{a}}\cdot {{K}_{b}}={{K}_{w}}\]\[{{K}_{b}}=\frac{{{K}_{w}}}{{{K}_{a}}}=\frac{{{10}^{-14}}}{3.5\times {{10}^{-4}}}=2.85\times {{10}^{-11}}\]


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