CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    A 700 pF capacitor is charged by a 50 V battery. The electrostatic energy stored by it is

    A)  \[17.0\times {{10}^{-8}}J\]                         

    B)  \[13.5\times {{10}^{-8}}J\]

    C)  \[9.5\times {{10}^{-9}}J\]                           

    D)  \[8.7\times {{10}^{-7}}J\]

    Correct Answer: D

    Solution :

                    \[E=\frac{1}{2}C{{V}^{2}}\]     \[=\frac{1}{2}\times (700\times {{10}^{-12}})\times 50\times 60\]     \[=8.7\times {{10}^{-7}}J\]


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