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CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    A capacitor of capacitance C has charge Q and stored energy is W. If the charge is increased to 2Q, the stored energy will be

    A)  \[\frac{W}{4}\]                                

    B)  \[\frac{W}{2}\]

    C)  \[2\,W\]                                             

    D)  \[4\,W\]

    Correct Answer: D

    Solution :

                    \[W=\frac{{{Q}^{2}}}{2C}\] \[W=\frac{{{(2Q)}^{2}}}{2C}\] \[W=4\frac{{{Q}^{2}}}{2C}\] \[W=4\,W\]


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