A) inner orbits of atoms
B) free electron existing in nucleus
C) decay of neutran in the nucleus
D) photon escaping from the nucleus
Correct Answer: B
Solution :
In \[\beta \text{-}\]decay, a beta minus particle \[({{\beta }^{-}})\]is an electron emission of p involves transformation of a neutron into a photon, an electron and a third particle called an antineutrino \[(\overline{v})\] \[_{0}{{n}^{1}}={{\,}_{1}}{{p}^{1}}+{{\,}_{-1}}{{\beta }^{0}}+v\]
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