CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    A bullet of mass 0.1 kg is fired with a speed of 100 m/s. The mass of gun being 50 kg. Then the velocity of recoil become

    A)  0.05 m/s                             

    B)  0.5 m/s 

    C)  0.1 m/s                               

    D)  0.2 m/s

    Correct Answer: D

    Solution :

                    Here, mass of the bullet \[{{m}_{1}}=0.1\,kg\] Speed of bullet \[{{v}_{1}}=100\,\,m\text{/}s\] Mass of the gun \[{{m}_{2}}=50\,kg\] According to the law of conservation of momentum is \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\] \[0.1\times 180=50\times {{v}_{2}}\] \[{{v}_{2}}=\frac{0.1\times 100}{50}=0.2\,m\text{/}s\]


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