A) \[-\,41\text{ }kJ\text{ }mo{{l}^{-1}}\]
B) \[-1312\,kJ\text{ }mo{{l}^{-1}}\]
C) \[-164\,kJ\,mo{{l}^{-1}}\]
D) \[-\,82\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: D
Solution :
The energy of second Bohr orbit of hydrogen atom \[({{E}_{2}})\] is \[-\,328\,kJ\,mo{{l}^{-1}}\]because \[{{E}_{n}}=-\,\frac{1312}{{{(2)}^{2}}}kJ\,mo{{l}^{-1}}\] \[\therefore \] \[{{E}_{n}}=-\,\frac{1312}{{{n}^{2}}}kJ\,mo{{l}^{-1}}\] If \[n=4\] \[\therefore \] \[{{E}_{4}}=-\frac{1312}{{{(4)}^{2}}}kJ\,mo{{l}^{-1}}\] \[=-\,82\,kJ\,mo{{l}^{-1}}\]
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