A) \[{}_{28}^{58}Ni\]
B) \[{}_{27}^{59}Co\]
C) \[{}_{28}^{60}Ni\]
D) \[{}_{27}^{60}Co\]
Correct Answer: C
Solution :
\[{}_{28}N{{i}^{60}}+{}_{0}{{n}^{1}}\xrightarrow{{}}{}_{27}C{{o}^{60}}+\,{}_{1}{{H}^{1}}\](n, p means that neutron attacks and proton liberates).
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