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CMC Medical CMC-Medical VELLORE Solved Paper-2012

  • question_answer
    If a body of mass m is projected at an angle of \[45{}^\circ \]with the horizontal, then total change in momentum when it strikes the ground will be (Take air resistance negligible)

    A)  \[mv\]                                

    B)  \[\sqrt{2}\,mv\]

    C)  \[\frac{mv}{\sqrt{2}}\]                                

    D)  \[2\,mv\]

    Correct Answer: B

    Solution :

                    Change in momentum \[=\,2mv\,\sin \theta \] \[=\,2mv\,\sin \frac{\pi }{4}\] \[=\sqrt{2}\,mv\]


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