2. Solved Papers
  3. CMC Medical

CMC Medical CMC-Medical VELLORE Solved Paper-2012

  • question_answer
    A mass of 10 kg is sliding along a rough horizontal surface. If the coefficient of friction is \[\frac{1}{\sqrt{3}},\] then the least force which acts  at an angle of \[30{}^\circ \] to horizontal is (Take g= 10 \[m\text{/}{{s}^{2}}\])

    A)  25 N                                     

    B)  50 N

    C)  50 n                                      

    D)  100N

    Correct Answer: B

    Solution :

                    Let F force is acting at an angle \[30{}^\circ \]with horizontal. For condition of motion,     \[F=\mu R\] \[F\cos 30{}^\circ =\mu \,(mg-F\sin 30{}^\circ )\]


You need to login to perform this action.
You will be redirected in 3 sec spinner