A) zero
B) infinity
C) \[2\times {{10}^{10}}N\text{-}{{m}^{2}}\]
D) \[3\times {{10}^{10}}N\text{-}{{m}^{-2}}\]
Correct Answer: B
Solution :
We know that, \[y=2\eta \,(1+\sigma )\] \[\therefore \] \[3\eta =2\eta \,(1+\sigma )\] \[\Rightarrow \] \[\sigma =\frac{3}{2}-1=\frac{1}{2}\] Substituting the value ofo in the expression. \[Y=3K(1-2\sigma )\] \[K=\frac{Y}{3\,(1-2\sigma )}=\infty \]
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