A) \[N{{H}_{4}}CNS\]
B) Dimethyl glyoxime in \[N{{H}_{4}}OH\] / alcoholic solution or DMG
C) \[{{H}_{2}}S\]gas
D) None of the above
Correct Answer: A
Solution :
\[N{{H}_{4}}CNS\]is the reagent used to identify\[C{{o}^{2+}}.\] \[CoC{{l}_{2}}+4N{{H}_{4}}SCN\xrightarrow{{}}\]\[\underset{Blue\,\,colour}{\mathop{{{(N{{H}_{4}})}_{2}}[Co{{(SCN)}_{4}}]}}\,+2N{{H}_{4}}Cl\] \[N{{H}_{4}}CNS\]can be used to make distinction between \[C{{u}^{2+}}\]and \[C{{o}^{2+}}\]. \[CuC{{l}_{2}}+2N{{H}_{4}}SCN\xrightarrow{{}}\underset{Black\,ppt.}{\mathop{Cu{{(SCN)}_{2}}}}\,\downarrow +2N{{H}_{4}}Cl\]
You need to login to perform this action.
You will be redirected in
3 sec
