A) \[k=A{{e}_{Ea/RT}}\]
B) \[\ln \frac{k}{A}=-\frac{{{E}_{a}}}{RT}\]
C) \[\log A=\log k+\frac{{{E}_{a}}}{2.303\,RT}\]
D) \[\log \left[ -\frac{{{E}_{a}}}{RT} \right]=\frac{k}{A}\]
Correct Answer: D
Solution :
\[\log \left[ \frac{-{{E}_{a}}}{RT} \right]=\frac{k}{A}\] \[k=A{{e}^{-{{E}_{a}}/RT}}\Rightarrow \frac{k}{A}={{e}^{-{{E}_{a}}/RT}}\] \[\frac{k}{A}=\log \left( \frac{-{{E}_{a}}}{RT} \right)\]
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