A) \[h=\frac{2s\,\cos \theta }{r\rho g}\]
B) \[v=\frac{1}{2\pi }\sqrt{\frac{mgl}{l}}\]
C) \[W=\frac{\partial u}{\partial x}+\frac{\partial u}{\partial y}+\frac{\partial u}{\partial z}\]
D) \[B=\frac{{{\mu }_{0}}l}{2\pi d}\]
Correct Answer: C
Solution :
As we know that Force, \[|F|=\left| \frac{\partial U}{\partial r} \right|\] where, U = potential energy and r = position But energy is equivalent to a work So, \[E\ne \frac{\partial U}{\partial r}\]
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