CMC Medical CMC-Medical Ludhiana Solved Paper-2014

  • question_answer
    A fly-wheel of mass 25 kg has a radius of 0.2m It is making 240 rpm. What is the torque necessary to bring to rest in 20 s?

    A)  \[2\pi \,N\text{-}m\]                    

    B)  \[0.4\pi \,N\text{-}m\]

    C)  \[\frac{2}{\pi }\,N\text{-}m\]                   

    D)  \[4\pi \,N\text{-}m\]

    Correct Answer: B

    Solution :

                    Angular acceleration \[\alpha =\frac{2\pi n}{t}\]     \[=\frac{2\pi \times \frac{240}{60}}{20}\]     \[=\frac{2\pi \times 4}{20}\] \[\alpha =\frac{2\pi }{5}\] Torque, \[\tau =\mathbf{/}\alpha \] \[\tau =M{{R}^{2}}\alpha \]    \[=25\times (0.04)\times \frac{2\pi }{5}\]    \[=0.4\pi \,N\text{-}m\]


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