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CMC Medical CMC-Medical Ludhiana Solved Paper-2014

  • question_answer
    The potential difference between two parallel plates is\[{{10}^{4}}V\]. If the plates are separated by 0.5 cm, the force on an electron between the plates is

    A)  \[32\times {{10}^{-13}}N\]                         

    B)  \[0.32\times {{10}^{-13}}N\]

    C)  \[0.032\times {{10}^{-13}}N\]   

    D)  \[3.2\times {{10}^{-13}}N\]

    Correct Answer: D

    Solution :

                    The force \[F=\frac{eV}{d}\] \[=\frac{1.6\times {{10}^{-19}}\times {{10}^{4}}}{0.5\times {{10}^{-2}}}=3.2\times {{10}^{-13}}N\]


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