question_answer

Six dice are stacked on the floor as shown in the figure below. On each dice, the sum of numbers on opposite face is 7, i.e. if 1 is written on one face, then 6 is written on the face opposite it and so on.

What is the maximum possible sum of numbers on the 21 visible faces?

A) 88        

B)        89      

C) 96        

D)        147

Correct Answer: B

Solution :

Sol. [b]

Maximum sum of number

\[P\,\to \,20\]                  \[Q\,\to \,13\]

\[R\,\to \,18\]                  \[S\,\to \,13\]

\[T\,\to \,7\]                    \[U\,\to \,18\]

\[\therefore \] Total sum

= 20 + 13 + 18 + 13 + 7 + 18 = 89