A) 12
B) 9
C) 8
D) 6
Correct Answer: D
Solution :
Ans. \[{{\left( \frac{9}{7} \right)}^{3}}\times {{\left( \frac{49}{81} \right)}^{2x-6}}={{\left( \frac{7}{9} \right)}^{9}}\] \[\Rightarrow \] \[{{\left( \frac{9}{7} \right)}^{3}}\times {{\left( \frac{9}{7} \right)}^{-2(2x-6)}}={{\left( \frac{9}{7} \right)}^{-9}}\] \[\Rightarrow \] \[3-4x+12=-9\] \[\Rightarrow \] \[-4x=-9-15\] \[\therefore \] \[x=6\]
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