A) \[6\]
B) \[5\]
C) \[4\]
D) \[2\]
Correct Answer: B
Solution :
\[\begin{align} & MnO_{4}^{-}+8{{H}^{+}}+5{{e}^{-}}\xrightarrow{{}}M{{n}^{2+}}+4{{H}_{2}}O \\ & [F{{e}^{2+}}\xrightarrow{{}}F{{e}^{3+}}+{{e}^{-}}]\times 5 \\ & \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ & MnO_{4}^{-}+8{{H}^{+}}+5F{{e}^{2+}}\to M{{n}^{2+}}+5F{{e}^{3+}}+4{{H}_{2}}O \\ & \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ \end{align}\] \[\therefore \] Five electrons gets transferred.
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