Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2011

  • question_answer
    At \[27{}^\circ C\], the average kinetic energy of gas is \[6.25\times {{10}^{-21}}J\] At \[227{}^\circ C\] its average kinetic energy will be

    A)  \[52.2\times {{10}^{-21}}\text{J}\]         

    B)  \[5.22\times {{10}^{-21}}\text{J}\]

    C)  \[10.42\times {{10}^{-21}}\text{J}\]       

    D)  \[11.35\times {{10}^{-21}}\text{J}\]

    Correct Answer: C

    Solution :

    According to kinetic molecular theory of gases, kinetic energy of gas is directly proportional to its absolute temperature. \[\therefore \]  \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\]                 \[\frac{6.25\times {{10}^{-21}}}{{{E}_{2}}}=\frac{27+273}{227+273}\]                 \[\frac{6.25\times {{10}^{-21}}}{{{E}_{2}}}=\frac{300}{500}\]                 \[{{E}_{2}}=\frac{5}{3}\times 6.25\times {{10}^{-21}}\]                 \[=10.42\times {{10}^{-21}}J\]


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