A) \[0.5\]
B) \[1.0\]
C) \[1.5\]
D) \[2.0\]
Correct Answer: A
Solution :
\[He_{2}^{+}(2+2-1=3)=\sigma 1{{s}^{2}},\sigma *1{{s}^{1}}\]Bond order \[=\frac{{{N}_{b}}-{{N}_{a}}}{2}\](\[{{N}_{b}}\], = bonding electrons, \[{{N}_{a}}\], = anti bonding electrons) \[=\frac{2-1}{2}=\frac{1}{2}=0.5\]
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