A) \[n{{s}^{2}}n{{p}^{3}}\]
B) \[n{{s}^{2}}n{{p}^{4}}\]
C) \[n{{s}^{2}}n{{p}^{5}}\]
D) \[n{{s}^{2}}n{{p}^{6}}\]
Correct Answer: C
Solution :
Fluorine is the most electronegative element and its electronic configuration is as \[{{F}_{9}}=1{{s}^{2}},2{{s}^{2}},2{{p}^{5}}\] Thus, its outer electronic configuration is \[n{{s}^{2}}n{{p}^{5}}\].
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