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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    Two bodies of masses \[{{m}_{1}}\] and \[{{m}_{2}}\] have equal momentum. Their kinetic energies \[{{E}_{1}}\] and \[{{E}_{2}}\] are in the ratio

    A)  \[\sqrt{{{m}_{1}}:}\sqrt{{{m}_{2}}}\]                                     

    B) \[{{m}_{1}}:{{m}_{2}}\]

    C) \[{{m}_{2}}:{{m}_{1}}\]                                

    D) \[m_{1}^{2}:m_{2}^{2}\]

    Correct Answer: C

    Solution :

    Kinetic energy \[E=\frac{{{P}^{2}}}{2m}\] if bodies possess equal linear momenta, then\[E\propto \frac{1}{m}\] ie,  \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}\]


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