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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    The decay constant of radium is \[4.28\times {{10}^{-4}}\] per \[yr\]Its half-life is approximately

    A) \[1250\,yr\]                                       

    B) \[1620\,yr\]

    C) \[200\,yr\]                                         

    D) \[60\,yr\]

    Correct Answer: B

    Solution :

    Half-life \[{{T}_{1/2}}=\frac{0.693}{\lambda }\] \[=\frac{0.693}{4.28\times {{10}^{-4}}}\approx 1620yr\]


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