Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    A solenoid of 1.5 m length and 4.0 cm diameter possesses 10 turns/cm. A current of 5 A is flowing through it. The magnetic induction a axis inside the solenoid is

    A) \[\text{2}\,\text{ }\!\!\pi\!\!\text{ }\,\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-3}}}\,\text{T}\]                  

    B) \[\text{2}\,\text{ }\!\!\pi\!\!\text{ }\,\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-5}}}\,\text{T}\]

    C) \[\text{2}\,\text{ }\!\!\pi\!\!\text{ }\,\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-3}}}\,\text{T}\]                  

    D) \[\text{2}\,\text{ }\!\!\pi\!\!\text{ }\,\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-5}}}\,\text{T}\]

    Correct Answer: A

    Solution :

    Magnetic field \[B={{\mu }_{0}}ni\] \[=4\pi \times {{10}^{-7}}\times 5\times 1000\] \[=2\pi \times {{10}^{-3}}T\]


You need to login to perform this action.
You will be redirected in 3 sec spinner