A) \[{{F}^{-}}\]
B) \[O{{H}^{-}}\]
C) \[CH_{3}^{-}\]
D) \[NH_{2}^{-}\]
Correct Answer: C
Solution :
\[Electronegativity\,\propto \frac{1}{nucleophilicity}\] \[\therefore \] \[CH_{3}^{-}\] has the highest nucleophilicity.
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