A) \[-0.45\]
B) \[-0.50\]
C) \[-0.31\]
D) \[-0.53\]
Correct Answer: A
Solution :
Since HX is 20% ionised, vant's Hoff factor, \[i=1+(y-1)\alpha \] [\[\because \]\[y=2,\] as two particles are produced] \[=1+(2-1)0.2\] \[=1.2\] \[\Delta {{T}_{f}}=i{{k}_{f}}.m\] \[=1.2\times 1.86\times 0.2\] \[={{0.45}^{o}}C\] \[\Delta {{T}_{f}}={{T}_{1}}-{{T}_{2}}\] \[{{T}_{2}}={{0}^{o}}C-{{0.45}^{o}}C\] \[=-{{0.45}^{o}}C\]
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